15p^2+p=1

Solution for 15p^2+p=1 equation:

15p^2+p=1

We move all terms to the left:

15p^2+p-(1)=0

a = 15; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·15·(-1)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{61}}{2*15}=\frac{-1-\sqrt{61}}{30}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{61}}{2*15}=\frac{-1+\sqrt{61}}{30}
$